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Create A Program to Implement Rapid Engineering Solutions in Python Assignment Solution

June 25, 2024
Dr. Andrew Taylor
Dr. Andrew
🇨🇦 Canada
Python
Dr. Andrew Taylor, a renowned figure in the realm of Computer Science, earned his PhD from McGill University in Montreal, Canada. With 7 years of experience, he has tackled over 500 Python assignments, leveraging his extensive knowledge and skills to deliver outstanding results.
Key Topics
  • Instructions
    • Objective
  • Requirements and Specifications
Tip of the day
When doing Java assignments, pay attention to object-oriented principles like encapsulation and inheritance. Write clean, modular code, and always test with edge cases. Using meaningful class and method names will make your program easier to understand and debug.
News
The C++ library deal.II version 9.7, out July 2025, enhances the finite-element method toolkit with more mesh adaptivity, parallelization, and tutorial improvements—useful for numerical simulations or academic modelling work.

Instructions

Objective

Write a python assignment program to implement rapid engineering solutions.

Requirements and Specifications

program-to-implement-rapid-engineering-solutions-in-python

Source Code

import numpy as np import matplotlib.pyplot as plt if __name__ == '__main__': electron = np.loadtxt('electron_quantites.txt') ion = np.loadtxt('ion_quantites.txt') x = electron[:,0] # positions rho = ion[:,1] ki = electron[:,2] Te = electron[:,1] Ti = ion[:,2] ke = ion[:,3] n = ion[:,4] u = ion[:,5] p = ion[:,6] E = ion[:,7] # First, calculate du/dx dudx = np.divide(u[1:]-u[0:-1], x[1:]-x[0:-1]) # Calculate dTi/dx dTidx = np.divide(Ti[1:]-Ti[0:-1], x[1:]-x[0:-1]) # Calculate dTe/dx dTedx = np.divide(Te[1:] - Te[0:-1], x[1:] - x[0:-1]) # From equation (1b), calculate p0u0^2 + p0 eq1b = np.multiply(p[:-1],np.power(u[:-1],2)) + p[:-1] - (4/3)*np.multiply(n[:-1], dudx) # Equation (1c) eq1c = np.multiply(E[:-1], u[:-1]) - np.multiply(ki[:-1], dTidx) - np.multiply(ke[:-1],dTedx) + np.multiply(p[:-1],u[:-1]) - (4/3)*np.multiply(n[:-1], np.multiply(u[:-1], dudx)) plt.plot(eq1b) plt.plot(eq1c) plt.show()

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