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Create A Program to Implement Rapid Engineering Solutions in Python Assignment Solution

June 25, 2024
Dr. Andrew Taylor
Dr. Andrew
🇨🇦 Canada
Python
Dr. Andrew Taylor, a renowned figure in the realm of Computer Science, earned his PhD from McGill University in Montreal, Canada. With 7 years of experience, he has tackled over 500 Python assignments, leveraging his extensive knowledge and skills to deliver outstanding results.
Key Topics
  • Instructions
    • Objective
  • Requirements and Specifications
Tip of the day
Use Python libraries effectively by importing only what you need. For example, if you're working with data, using libraries like pandas and numpy can save time and simplify complex tasks like data manipulation and analysis.
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In 2024, the Biden-Harris Administration has expanded high-dosage tutoring and extended learning programs to boost academic achievement, helping programming students and others recover from pandemic-related setbacks. These initiatives are funded by federal resources aimed at improving math and literacy skills​

Instructions

Objective

Write a python assignment program to implement rapid engineering solutions.

Requirements and Specifications

program-to-implement-rapid-engineering-solutions-in-python

Source Code

import numpy as np import matplotlib.pyplot as plt if __name__ == '__main__': electron = np.loadtxt('electron_quantites.txt') ion = np.loadtxt('ion_quantites.txt') x = electron[:,0] # positions rho = ion[:,1] ki = electron[:,2] Te = electron[:,1] Ti = ion[:,2] ke = ion[:,3] n = ion[:,4] u = ion[:,5] p = ion[:,6] E = ion[:,7] # First, calculate du/dx dudx = np.divide(u[1:]-u[0:-1], x[1:]-x[0:-1]) # Calculate dTi/dx dTidx = np.divide(Ti[1:]-Ti[0:-1], x[1:]-x[0:-1]) # Calculate dTe/dx dTedx = np.divide(Te[1:] - Te[0:-1], x[1:] - x[0:-1]) # From equation (1b), calculate p0u0^2 + p0 eq1b = np.multiply(p[:-1],np.power(u[:-1],2)) + p[:-1] - (4/3)*np.multiply(n[:-1], dudx) # Equation (1c) eq1c = np.multiply(E[:-1], u[:-1]) - np.multiply(ki[:-1], dTidx) - np.multiply(ke[:-1],dTedx) + np.multiply(p[:-1],u[:-1]) - (4/3)*np.multiply(n[:-1], np.multiply(u[:-1], dudx)) plt.plot(eq1b) plt.plot(eq1c) plt.show()

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