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Defining Regular Expressions through Program In Haskell Assignment Solution

July 01, 2024
David Lee
David Lee
🇺🇸 United States
Haskell
David holds a Master's degree in Software Engineering and has been passionate about functional programming since his early studies. With over 500 WAI assignments under his belt, he excels at explaining core WAI concepts like request handling, middleware, and logging. David's expertise extends to functional testing frameworks like QuickCheck, ensuring students write well-tested and reliable WAI applications.
Key Topics
  • Instructions
  • Requirements and Specifications
Tip of the day
Focus on understanding pure functions and immutability first. Write small, testable functions and leverage pattern matching instead of complex conditionals. This makes Haskell code clearer, easier to debug, and more aligned with functional programming principles.
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In 2026 universities worldwide are rapidly integrating AI-powered educational software and tools—from intelligent tutors to adaptive coding platforms—into curricula to enhance programming education and automate feedback on assignments.

Instructions

Objective
Write a haskell assignment program that allows users to implement and define regular expressions.

Requirements and Specifications

For each of the three variables, write a regular expression (as a string) corresponding to the DFAs given below. Ensure that the regex you provide can be parsed using the parser provided in REP.hs.
For example,
*REP> parse (pREof pAlphabet) "A*B*"
Just (RSeq (RStar (RSym A)) (RStar (RSym B)))
You may use any of the posted sample code to check your answers, but only submit the regular expressions themselves.
regex1 should correspond to this DFA:
regex1-1
regex2 should correspond to this DFA:
regex2-2
regex3 should correspond to this DFA:
regex3-3
Screenshots of output
Define-regular-expressions-in-Haskell
Source Code
module HW5 where
-- imports added for doing tests in ghci
import Parser
import RE
import REP
regex1 = "(B|A+B)*"
regex2 = "A+B+|B+A+|e"
regex3 = "(BA)*(e|AA(BA|AA(BA)*AA)*(e|AA(BA)*))"

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