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  • GNU Prolog Assignment Help
  • Why Students Should Consider Seeking Help with GNU Prolog Assignments?
  • Implementation of Recursion with Factorial in GNU Prolog
  • Discover the Benefits of Using Our GNU Prolog Assignment Help Service
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Implementation of Recursion with Factorial in GNU Prolog

% Define the factorial function factorial(0, 1). % Base case: factorial of 0 is 1 factorial(N, F) :- N > 0, % Ensure N is positive N1 is N - 1, % Decrement N factorial(N1, F1), % Recursive call F is N * F1. % Compute factorial

Explanation:

This code snippet defines a simple recursive predicate to compute the factorial of a number. The factorial of a number NNN (denoted as N!N!N!) is the product of all positive integers less than or equal to NNN.

  1. Base Case: The first line, factorial(0, 1)., handles the base case where the factorial of 0 is defined as 1. This is a fundamental aspect of recursion where a function has a terminating condition.
  2. Recursive Case:The second clause defines how to compute the factorial for numbers greater than 0. It involves:
    • Decrementing the number NNN by 1 to make a recursive call.
    • Calling the factorial function recursively to compute the factorial of N−1N-1N−1.
    • Multiplying the result of the recursive call with NNN to get the factorial of NNN.

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